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The product of 0 and anything is $0$, and seems like it would be reasonable to assume that $0 Why should we use '\0' here? I'm perplexed as to why i have to account for this condition in my factorial function (trying to learn haskell).

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0.0.0.0 means that any ip either from a local system or from anywhere on the internet can access While using printf() if you have an string which is not \0 terminated then printf() keeps writing characters to stdout until a \0 is encountered, in short it might even print garbage It is everything else other than what is already specified in routing table.

12 %0 will never end, but it never creates more than one process because it instantly transfers control to the 2nd batch script (which happens to be itself)

But a windows pipe creates a new process for each side of the pipe, in addition to the parent process The parent process can't finish until each side of the pipe terminates. The loopback adapter with ip address 127.0.0.1 from the perspective of the server process looks just like any other network adapter on the machine, so a server told to listen on 0.0.0.0 will accept connections on that interface too. It is possible to interpret such expressions in many ways that can make sense

The question is, what properties do we want such an interpretation to have $0^i = 0$ is a good choice, and maybe the only choice that makes concrete sense, since it follows the convention $0^x = 0$ As we all know the ipv4 address for localhost is 127.0.0.1 (loopback address) What is the ipv6 address for localhost and for 0.0.0.0 as i need to block some ad hosts.

This can happen either from a timeout, xhr abortion or a firewall stomping on the request.

Line 1 column 1 (char 0) also happens when the first line in the json response is invalid Example response from running an az cli command is [warning The default kind for created storage account will change to 'storagev2' from 'storage' in the future, '{',. Ll designates a literal as a long long and ul designates one as unsigned long and 0x0 is hexadecimal for 0

So 0ll and 0x0ul are an equivalent number but different datatypes The former is a long long and the latter is an unsigned long. Note that \0 is needed because most of standard c library functions operate on strings assuming they are \0 terminated